dfdx=2x,f(0)=1\frac{df}{dx}=2x, f(0)=1dxdf=2x,f(0)=1 ആയ ഏകദം f(x) ഏത് ? A(x+1)²Bx² + 1C2x + 1Dx + 1Answer: B. x² + 1 Read Explanation: df = 2xdx f= 2x² / 2 + C f(0)=1 => 1= 0 + C C=1 f(x)=x²+1Read more in App