If the zeros of the quadratic polynomial$ax^2+bx+c$,c≠ 0 are equal , then :

Zeros of $p(x) = x^2-27$are:

Find the value of k if x - 1 is a factor of $4x^3+3x^2+4x+k$

Find the value of k if x - 1 is a factor of $2x^3+x^2-4x+k$

Find the value of k if x - 1 is a factor of $4x^3+3x^2-4x+k$

The expression $4x^2-px+7$ leaves the reminder -2 when divided by x - 3. Find the value of p

Find the reminder when $x^3-bx^2+6x-b$is divided by $x-b$

Find the reminder when $4x^2+3x+1$is divided by $2x +5$

Find the reminder when $4x^2+3x+1$is divided by $x +1$

Find the reminder when $x^4+x^3-2x^2+x+1$is divided by $x-1$

Find the degree of the polynomial p(x)q(x); $p(x)=2x^2+4x+2$,$q(x)=4x+6$

What is the degree of p(x)+q(x):

$p(x)=4x^4+3x^2+6x+9$,$q(x)=5x^4+6x^3+8$

Find the reminder when $p(x)=4x^4+6x^3+6x+6$ is divided by $x+2$

$p(x) =2x^2+3x+7$,$q(x)=6x^2+8x-9$Find $p(x)\times{q(x)}$

Find the reminder when $p(x)=2x^4+4x^2-1$is divided by $x+1$

What will come in place of the question mark (?) in the following question?

$\frac{3}{5}+\frac{5}{3}+?=\frac{7}{3}$

If $\frac{-a}{b}\times{\frac{c}{d}}=1$ then, $\frac{c}{d}=?$

$p(x) =2x^2+3x+7$,$q(x)=6x^2+8x-9$Find q(x)-p(x)

Solve; $\frac{1}{13}\div{\frac{1}{13}}\div{\frac{1}{13}}\div{\frac{1}{13}}\div{\frac{1}{13}}=?$

$p(x) =2x^2+3x+7$,$q(x)=6x^2+8x-9$Find p(x)+q(x)

Find:

$\frac{3}{4}+[\frac{3}{4}+\frac{3}{4}\div{(\frac{3}{4}+\frac{3}{4})}]=?$

Which one of the following is the largest fraction?

6/7, 5/6, 7/8, 4/5

Express $4.\bar{12}$ in fraction.

Which of the fractions given below, when added to $\frac{5}{8}$, give 1?

Which of the given fractions is NOT equal to $\frac{9}{17}?$

Find the value of ‘?’ in the following question?

$\frac{1}{4}\times{\frac{1}{5}}\div{\frac{1}{8}}+\frac{4}{5}\times{1}{2}\div{2}{3}=?$

There are total 200 students in a school, of which $\frac{2}{5}$ th are boys. Find the number of girls in the school.

What should come in place of the question mark (?) in the following questions?

$\frac{6}{2}\times\frac{10}{2}\div{\frac{6}{2}}\times{\frac{6}{2}}\times{6^2}=?$

$\frac{189}{135}$ when written in the simplest form is:

Convert $0.\bar{6}$ into a fraction:

Simplify: $7\frac{1}{5}\div1\frac{1}{35}\times\frac{3}{35}$

Simplify:

$(\frac{1-1}{10})(\frac{1-1}{11})(\frac{1-1}{12})-(\frac{1-1}{99})(\frac{1-1}{100})=?$